4y^2+4y+3=0

Solution for 4y^2+4y+3=0 equation:

Simplifying
4y2 + 4y + 3 = 0

Reorder the terms:
3 + 4y + 4y2 = 0

Solving
3 + 4y + 4y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
0.75 + y + y2 = 0

Move the constant term to the right:

Add '-0.75' to each side of the equation.
0.75 + y + -0.75 + y2 = 0 + -0.75

Reorder the terms:
0.75 + -0.75 + y + y2 = 0 + -0.75

Combine like terms: 0.75 + -0.75 = 0.00
0.00 + y + y2 = 0 + -0.75
y + y2 = 0 + -0.75

Combine like terms: 0 + -0.75 = -0.75
y + y2 = -0.75

The y term is y.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
 + 0.25 + y2 = -0.75 + 0.25

Combine like terms:  + 0.25 = 1.25
1.25 + y2 = -0.75 + 0.25

Combine like terms: -0.75 + 0.25 = -0.5
1.25 + y2 = -0.5

Factor a perfect square on the left side:
(y + 0.5)(y + 0.5) = -0.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.